Решение по адм. дело №576/2023 на Административен съд - Стара Загора

Номер на акта: 368
Дата: 29 януари 2025 г.
Съдия: Златко Мазников
Дело: 20237240700576
Тип на делото: Административно дело
Дата на образуване: 12 септември 2023 г.

Съдържание на акта

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(!) !640/2014, ?@8 ?@8;030=5 =0 >B=>A8<8B5 E8?>B578 70 =587?J;=5=85, :>5B> =5 70AO30 ?>4?><030=0B0 459=>AB 2 FO;>AB 8 >B:;>=5=85B> >B 70;>65=8B5 2 187=5A ?;0=0 D8=0=A>28 ?0@0<5B@8 8 B578 ?> >B=>H5=85 =0 CAB>9G820B0 705B>AB =5 2J7?@5?OBAB20B ?>AB830=5B> =0 F5;8B5 =0 ?@54>AB025=>B> ?>4?><030=5 8 87?J;=5=85B> =0 ?@>5:B0. @8 A?0720=5 =0 878A:20=5B> ?> G;. 3, 0;. 1 >B @028;0B0 5 >?@545;5=0 54=0 >1I0 D8=0=A>20 :>@5:F8O 70 425B5 =0@CH5=8O, @07<5@JB =0 :>OB> 5 @025= =0 =09-28A>:8O ?@8;>68< ?@>F5=B &ndash; 100%. ! >3;54 =0 ?>A;54=>B> AJ4JB ?@85<0, G5 ?@028;=> 5 >?@545;5= 8 @07<5@JB =0 A;5420I0B0 A5 D8=0=A>20 :>@5:F8O ?> G;. 70, 0;. 1, B. 7 >B #!$!#.</p> <p dir="ltr" style="margin-right:40px; margin-left:19px; text-align:justify; text-indent:42.5pt">!J>B25BAB285B> =0 >160;20=8O 04<8=8AB@0B825= 0:B A <0B5@80;=8O 70:>= 2 ?>A>G5=8O A<8AJ;, >?@545;O 8 AJ>B25BAB285B> <C A F5;B0 =0 70:>=0 &ndash; 70I8B0 =0 D8=0=A>28B5 8=B5@5A8 =0 !JN70 (G;5= 58, &sect; 1 >B  53;0<5=B (!) !1306/2013), ?>@048 :>5B>, 01AB@0E8@09:8 A5 >B CAB0=>25=8B5 ?@54?>AB02:8 70 >1O2O20=5 =0 =8I>6=>ABB0 <C, >BAJAB20 >A=>20=85 70 >B<O=0B0 <C ?> G;. 146, B. 5 >B . 5 5 =0;8F5 8 =0@CH5=85 =0 ?@8=F8?0 =0 ?@>?>@F8>=0;=>AB ?> G;. 6 >B , 4>:>;:>B> :0:B> 15H5 ?>A>G5=>, >?@545;5=8OB @07<5@ =0 D8=0=A>20B0 :>@5:F8O, >BG8B0 :0:B> AB5?5=B0 =0 87?J;=5=85 =0 70;>65=8B5 2 187=5A ?;0=0 ?>:070B5;8, B0:0 8 ?@>4J;68B5;=>ABB0 =0 =587?J;=5=85B>.</p> <p dir="ltr" style="margin-right:40px; margin-left:19px; text-align:justify; text-indent:42.5pt">@54284 87E>40 =0 A?>@0, >1CA;>25= >A=>2=> >B AJ>1@065=8OB0 A2J@70=8 A =5>1E>48<>ABB0 >B >1O2O20=5 =8I>6=>ABB0 =0  $, 8A:0=5B> =0 60;1>?>40B5;O 70 @07=>A:8 A5 O2O20 >A=>20B5;=>, :0B> 2 B565AB =0 $ A;5420 1J45 2J7;>65=> 70?;0I0=5B> =0 AC<0B0 >B 9 951.20 ;2., >B :>8B> 1700.00 ;2. 70?;0B5=0 4J@602=0 B0:A0, 900.00 ;2. 2J7=03@0645=85 70 873>B2O=5 =0 ! 8 7 351.20 ;2. 4>3>2>@5=> 8 70?;0B5=> 2J7=03@0645=85 70 548= 042>:0B.</p> <p dir="ltr" style="margin-right:40px; margin-left:19px; text-align:justify; text-indent:42.5pt">>48< >B 3>@=8B5 <>B828, 4<8=8AB@0B825= AJ4 !B0@0 03>@0 =0 >A=>20=85 G;. 172, 0;. 2, ?@54;>65=85 ?J@2> >B </p> <p class="firstline" dir="ltr" style="margin-right:-26px; text-indent:0cm; text-align:justify">&nbsp;</p> <p align="center" dir="ltr" style="margin-right:36px; margin-left:19px; text-align:center; text-indent:0cm"><b>  (  :</b></p> <p dir="ltr" style="margin-right:36px; margin-left:19px; text-align:justify; text-indent:42.5pt">&nbsp;</p> <p dir="ltr" style="margin-right:36px; margin-left:19px; text-align:justify; text-indent:42.5pt"><b>//  )</b>  5H5=85 70 =0;030=5 =0 D8=0=A>20 :>@5:F8O ! 24/312/02621/3/01/04/02 A 87E. ! 01-6500/8537 >B 22.11.2022 3., 874045=> >B 87?J;=8B5;=8O 48@5:B>@ =0 J@6025= D>=4 &bdquo;5<545;85&ldquo;, A :>5B> =0 " &bdquo;. &ndash; . .&ldquo; 5 >?@545;5=0 D8=0=A>20 :>@5:F8O 2 >:>=G0B5;5= @07<5@ =0 229 810,21 ;2., ?@54AB02;O20I0 100% >B ?@54>AB025=0B0 1572J7<574=0 D8=0=A>20 ?><>I ?> A:;NG5= 4>3>2>@ ! 24/312/02621 >B 02.10.2014 3. 70 >B?CA:0=5 =0 D8=0=A>20 ?><>I 2J2 2@J7:0 A @50;870F8O =0 ?@>5:B &ndash; &bdquo;JI0 70 3>AB8 2 [=0A5;5=> <OAB>] 10=O, <5AB=>AB &bdquo;5@5=O&ldquo;, ?> <O@:0 312 &bdquo;>4:@5?0 70 AJ74020=5 8 @0728B85 =0 <8:@>?@54?@8OB8O&ldquo; >B  ! 2007-2013, ?>4:@5?5=0 >B $ ! .</p> <p dir="ltr" style="margin-right:36px; margin-left:19px; text-align:justify; text-indent:42.5pt">&nbsp;</p> <p dir="ltr" style="margin-right:36px; margin-left:19px; text-align:justify; text-indent:42.5pt"><b>!*</b> J@6025= &bdquo;$>=4 75<545;85&ldquo; [=0A5;5=> <OAB>] 40 70?;0B8 =0 " &bdquo;.-. .&ldquo;,  *********, AJA A540;8I5 8 04@5A =0 C?@02;5=85 [=0A5;5=> <OAB>] 10=O, >1;0AB !B0@0 03>@0, &bdquo;!B>?0=A:8 42>@ &ndash; !.&ldquo; >D8A 1, AC<0B0 >B 9 951.20 ;520 (4525B E8;O48 4525BAB>B8= ?5B45A5B 8 548= ;520 8 42045A5B AB>B8=:8), ?@54AB02;O20I0 =0?@025=8 @07=>A:8 ?> 45;>B>.</p> <p dir="ltr" style="margin-right:36px; margin-left:19px; text-align:justify; text-indent:42.5pt">&nbsp;</p> <p dir="ltr"> 5H5=85B> ?>4;568 =0 >160;20=5 A :0A0F8>==0 60;10 ?@54 J@E>2=8O 04<8=8AB@0B825= AJ4 2 14-4=525= A@>: >B AJ>1I020=5B> <C =0 AB@0=8B5, 254=> A ?@5?8A >B =53>.</p> </div> <!--clear_end--> <p dir="ltr">&nbsp;</p> <div class="BreakerSignature" dir="ltr" style="margin: 30px 0 200px 0;"> <table border="0" class="body-text" dir="ltr" style="width: 100%;"> <tbody> <tr> <td style="text-align: right; vertical-align: top;"><strong><span style="color:black;"><span style="font-family:ms sans serif,sans-serif; text-transform: uppercase;"><span class="printDefinition" id="591J; @54A540B5;/!J48O">!J48O</span>: </span></span></strong></td> <td style="width: 205px;">&nbsp;</td> </tr> <tr> <td style="text-align: right; vertical-align: top;padding-top: 20px">&nbsp;</td> <td style="width: 205px;padding-top: 20px">&nbsp;</td> </tr> </tbody> </table> </div>