Решение по адм. дело №1606/2024 на Административен съд - Пловдив

Номер на акта: 1217
Дата: 10 февруари 2025 г. (в сила от 12 март 2025 г.)
Съдия: Петър Касабов
Дело: 20247180701606
Тип на делото: Административно дело
Дата на образуване: 25 юли 2024 г.

Съдържание на акта

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C:;5=, >1;0AB ;>2482, A F5; ?@><O=0 =0 ?@54=07=0G5=85B> 8< 70 68;8I=> 70AB@>O20=5 , :0:B> A;5420: >B  A  40467.17.2 8 >B  40467.17.3 A5 >1@07C20B B@8 1@>O C@53C;8@0=8 ?>75<;5=8 8<>B8: # 17.220  68;. 70AB@., 17.221  68;. 70AB@., 17.222  68;. 70AB@., :0B> @53C;0F8>==8B5 ;8=88 <8=020B AJ3;0A=> G5@25=8B5 8 A8=8 ;8=88 8 >7=0G5=8O =0 ?@8;>65=8O ?@>5:B 8 B@0A8@>2JG5= ?;0=; >?@545;O A2>1>4=>, =8A:> 70AB@>O20=5 A  4> 10 < 2 >3@0=8G8B5;=0B0 7>=0, >7=0G5=0 A G5@25= ?C=:B8@  ;8=8O =0 70AB@>O20=5; >?@545;O 7>=0 <  A CAB@>9AB25=8 ?>:070B5;8: ;. 70AB@.  4> 60%; 8=B  1,2; ;. >75;5=O20=5  <8=. 40%.</p> <p dir="ltr" style="text-align:justify"><b>12. </b>>4045=> 5 70O2;5=85 2E. 5756/09.07.2024 3. >B . . !. 8 . . !. 4> :<5B0 =0 >1I8=0 C:;5=, 70 ?@>25640=5 =0 ?@>F54C@0 ?> CG@54O20=5 ?@02> =0 ?@5<8=020=5 ?> G;. 36 >B 0:>=0 70 >?0A20=5 =0 A5;A:>AB>?0=A:>B> 8<CI5AB2>, A F5; >A83C@O20=5 =0 4>ABJ? 4> 8<>B 40467.17.4, =0E>4OI A5 2 <5AB=>ABB0 A0:0 , 75<;8I5 =0 3@. C:;5=, >1I. C:;5=, >1;0AB ;>2482.</p> <p dir="ltr" style="text-align:justify"><b>13.</b>  E>40 =0 AJ451=>B> ?@>872>4AB2> A5 4>?CA=0 AJ451=> - B5E=8G5A:0 5:A?5@B870 A 25I8 ;8F5 0@E. .  ., G88B> 70:;NG5=8O A5 ?@85 157 2J7@065=8O >B AB@0=8B5. :A?5@BJB CAB0=>2O20, G5 :J< <><5=B0 =0 >4>1@O20=5 =0 ?@>F5A=8OB # -   8<>BJB =0 60;1>?>40B5;8B5   40467.17.4, =5 5 C@53C;8@0=, AJI8OB 5 AJA AB0BCB =0 75<545;A:0 75<O, " =820 , 872J= >:>;>2@JAB=8O ?>;83>= =0 3@. C:;5=. ! >4>1@5=8O # =5 A5 ?@5428640 ?> >B=>H5=85 =0  40467.17.4: ?@><O=0 2 @53C;0F8OB0, >B=5<0=5 8;8 ?@84020=5 =0 ?;>I8, =>2> A2J@70=> 70AB@>O20=5, ?@><O=0 2 70AB@>O20=5B>, =0<0;5=8 @07AB>O=8O 8;8 >3@0=8G5=85 2 @568<0 =0 70AB@>O20=5 8 ?>;720=5. B=>A=> 8<>B8B5, ?@54<5B =0 ?;0=0 ( A  40467.17.2 8  40467.17.3), 5:A?5@BJB CAB0=>2O20, G5 ?@8 >1@07C20=5B> =0 # 17.221, 68;. AB@. A ?;>I 445 :2.<. 8 ;8F5  16,06 <, 5 4>?CA=0B> =0<0;5=0 ?;>I ?>4 500 :2.<., => 2 @0<:8B5 =0 4>?CAB8<0B0 54=0 ?5B0 ?> G;. 19, 0;. 4 #".</p> <p dir="ltr" style="text-align:justify">B=>A=> 4>ABJ?0 4> ?JB 70 8<>B  40467.17.4, 25I>B> ;8F5 CAB0=>2O20, G5 B0:J2 =5 5 18; ?@542845= ?> 0@B0B0 =0 2J7AB0=>25=0B0 A>1AB25=>AB 70 75<;8I5B> =0 3@. 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