Решение по адм. дело №22/2024 на Административен съд - Сливен

Номер на акта: 550
Дата: 14 март 2024 г. (в сила от 14 март 2024 г.)
Съдия:
Дело: 20247220700022
Тип на делото: Административно дело
Дата на образуване: 11 януари 2024 г.

Съдържание на акта

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"578 2J?@>A8 ?>4@>1=> A0 @073;540=8 >B :><8A8OB0 =0B>20@5=0 A @07A;5420=5B> =0 A;CG0O, :0B> ?> 45;>B> =5 A0 CAB0=>25=8 >1AB>OB5;AB20, :>8B> 40 87:;NG0B >B3>2>@=>ABB0 =0 60;1>?>40B5;O. !;5420 40 A5 ?>A>G8, G5 2A8G:8 2J7@065=8O =0 60;1>?>40B5;O 87;>65=8 2 =53>28 >1OA=5=8O A0 ?@>25@5=8 >B =07=0G5=0B0 :><8A8O.</p> <p class="m" dir="ltr" style="text-indent:2.0cm; text-align:justify">8?A20B >A=>20=8O 70 >B<O=0 =0 >160;20=0B0 70?>254, A2J@70=8 A >?@545;O=5B> =0 @07<5@0 =0 =0:070=85B>. !J3;0A=> <a href="apis://Base=NARH&amp;DocCode=41299&amp;ToPar=Art199_Al2&amp;Type=201">G;. 199, 0;. 2 >B  </a> =0:070=85B> &quot;?8A<5=> ?@54C?@5645=85&quot; A5 =0;030 70 A@>: >B B@8 4> H5AB <5A5F0. @028;=> 2 B078 2@J7:0  5 275; ?@54284 :0:B> A<5:G020I8B5, B0:0 8 >B53G020I8B5 28=0B0 >1AB>OB5;AB20. @30=JB 5 275; ?@54284 =0;8G85B> =0 ?@54E>4=8 =03@048 8 ;8?A0 =0 48AF8?;8=0@=8 =0:070=8O 2 A;C651=0B0 459=>AB =0 ., :0B> 5 >?@545;5;8 =0:070=85B> 2 <8=8<0;5= @07<5@. 0?>254B0 5 874045=0 2 AJ>B25BAB285 A F5;B0 =0 70:>=0, =0A>G5=0 :J< >A83C@O20=5 A?0720=5B> =0 A;C651=0B0 48AF8?;8=0 >B >@30=8B5 =0 @540. 5 A0 =0;8F5 >A=>20=8O 70 >A?>@20=5 ?> <a href="apis://Base=NARH&amp;DocCode=2024&amp;ToPar=Art146_Pt4&amp;Type=201">G;. 146, B. 4</a> 8 <a href="apis://Base=NARH&amp;DocCode=2024&amp;ToPar=Art146_Pt5&amp;Type=201">5 >B </a>.</p> <p class="m" dir="ltr" style="text-indent:2.0cm; text-align:justify">@8 872J@H5=0B0 FO;>AB=0 ?@>25@:0 70 70:>=>AJ>1@07=>AB =0 0:B0 ?> @540 =0 G;. 168, 0;. 1 >B  =5 A5 >B:@8E0 >A=>20=8O, :>8B> 40 4>2540B 4> >B<O=0B0 <C. 0;10B0 :0B> =5>A=>20B5;=0 A;5420 40 A5 >BE2J@;8.</p> <p class="m" dir="ltr" style="text-indent:2.0cm; text-align:justify">! >3;54 87E>40 =0 A?>@0, ?@5B5=F8OB0 =0 >A?>@20I8O 70 ?@8AJ640=5 =0 =0?@025=8B5 ?> 45;>B> @07=>A:8 5 =5>A=>20B5;=0.</p> <p class="m" dir="ltr" style="text-indent:2.0cm; text-align:justify">B25B=8:JB =5 5 ?@5B5=48@0; @07=>A:8.</p> <p class="m" dir="ltr" style="text-indent:2.0cm; text-align:justify">>45= >B 3>@587;>65=>B> 8 =0 >A=>20=85 G;. 172, 0;. 2, ?@54;. ?>A;54=> >B , 4<8=8AB@0B825= AJ4 - !;825=</p> <p dir="ltr" style="text-align:justify; text-indent:35.4pt">&nbsp;</p> <p align="center" dir="ltr" style="text-align:center"><b> (:</b></p> <p dir="ltr" style="text-align:justify; text-indent:35.4pt">&nbsp;</p> <p dir="ltr" style="text-align:justify; text-indent:2.0cm"><b>"%* / </b>60;10B0 =0 !. %. . ?@>B82 0?>254 ! 3437-8/03.01.2024 3. 874045=0 >B 8@5:B>@0 =0  =0  &ndash; !;825=.</p> <p dir="ltr" style="text-align:justify; text-indent:2.0cm"> 5H5=85B> =0 >A=>20=85 G;. 211 >B  =5 ?>4;568 =0 >160;20=5.</p> <p dir="ltr" style="text-align:justify; text-indent:2.0cm"> 5H5=85B> 40 A5 AJ>1I8 =0 AB@0=8B5 G@57 87?@0I0=5 =0 ?@5?8A >B AJI>B>.</p> </div> <!--clear_end--> <p dir="ltr">&nbsp;</p> <div class="BreakerSignature" dir="ltr" style="margin: 30px 0 200px 0;"> <table border="0" class="body-text" dir="ltr" style="width: 100%;"> <tbody> <tr> <td style="text-align: right; vertical-align: top;"><strong><span style="color:black;"><span style="font-family:ms sans serif,sans-serif; text-transform: uppercase;"><span class="printDefinition" id="591J; @54A540B5;/!J48O">!J48O</span>: </span></span></strong></td> <td style="width: 205px;">&nbsp;</td> </tr> <tr> <td style="text-align: right; vertical-align: top;padding-top: 20px">&nbsp;</td> <td style="width: 205px;padding-top: 20px">&nbsp;</td> </tr> </tbody> </table> </div>